The acronym BASE stands for building, antennae, span, and earth; which make up a comprehensive list of what kinds of fixed objects BASE jumpers plummet from. Span is a term that includes all sorts of bridges, or any other structures that span over a valley or chasm. Earth means anything from cliffs to mountains to canyons.

BASE jumping is very dangerous for a variety of reasons, but the most common causes of injury and death have to do with failure to maintain a clear area around the athlete during the jump and/or the landing. If the wind is against them or if they make a mistake during the launch of their jump, athletes sometimes collide with the object that they have jumped from. Because BASE jumping areas are usually not designated for this guerilla-style sport, the makeshift landing targets that jumpers aim for are rarely large enough to allow for a safe jump. As a result many BASE enthusiasts meet with serious and sometimes fatal injuries because they haven’t been able to steer themselves to the landing area in time.

Many people compare BASE jumping to bungee jumping without a bungee cord, but it is actually much closer to skydiving without an airplane. Jumpers practice many of the same techniques that divers use to maintain stability and altitude awareness while they are in the air. Before becoming a BASE jumper, an athlete must complete a full course of skydiver training. Once they have their full skydiving certification, the next step for anyone interested in BASE is to find a mentor in the jumping community who can teach them how to take on these ambitious freefalls. Only experienced divers can even contemplate a BASE jump because this kind of unguided and somewhat unpredictable activity requires razor sharp awareness of altitude, along with stellar free fall technique.

BASE jumping is one of the most dangerous sports practiced today. Every year, BASE jumping leads to several fatalities, and most major BASE societies and clubs have seen at least one member perish in pursuit of the sport that he or she loved. Because no two jumps are alike, it is very difficult to predict what will happen once you start plummeting towards the ground. This means that to survive a BASE jump you need to have a very level head, an ability to react to surprises without panicking, and lightning speed reflexes that will allow you to make instantaneous adjustments in your position or your trajectory. However, no amount of experience can guarantee that you will complete your jump without mishap, so even very accomplished jumpers are taking serious risks every time they prepare to hurl themselves off of a building, antennae, span, or natural cliff.

Bungee jumping is quite a dangerous sport and quite the adrenaline rush as well. You can jump from all kinds of places you just need to learn how to jump before you make your move. To make your jumps even more insane you can jump from moving bases like a helicopter, hot air balloon or something like that. There are no limits really when it comes to bungee jumping.

The word bungee came around in the 1930s but the first bungee jump didn’t happen until 1979. They used some kind of vine to do there bungee jumps with but I would figure that would hurt their feet as they fell and then were snapped back up that would sound like it would rip there ankles away from there legs. I don’t know how it is supposed to work but I guess it did.

A J Hackett of New Zealand was the first one to do a commercial bungee jump. Even though many other people had already done many jumps he was the first one to jump from monuments like the Eiffel tower. There are many places that you could make a jump from but you must learn how to jump before you just go and do it.

The whole point of the jump is the rubber rope or whatever you want to call it. When a jumper is falling when he hits the end of the rope the rope will snap back causing the jumper to go back in the upward direction and that will happen until all of the energy that came with the jump is neutralized. After you jump the first time and get to the bottom you will be snapped back towards where you jumped but will not come even close to the platform in which you jumped from.

There are many different kinds of bungee sports but I only know of bungee jumping but if you ever want to bungee jump all you need to do is look up that in the phone book or go online and try and look them up. If you still cannot find what you are looking for then you just need to keep looking until you find what it is that you are looking for.

If you still cannot find what you seek on the internet then you just need to either give up on the bungee jumping or you need to keep looking for it. I am pretty sure that you can find a place that does bungee jumping. If you cannot then you can go to a theme park and they may have something similar to what bungee jumping is.

So if that is what you want to do then you just need to get you a ticket for a theme park and try to go find a park that does some kind of bungee jumping. Even though it may cost more then the other type of bungee jump you will still feel the same rush as you would with a regular bungee.

“An adventurer plans to jump of the high of a bridge tied in an elastic (a radical sport known for ‘bungee jumping’) cable. The other extremity of the cable is tied in the bridge. In the beginning, the jumper’s movement is a free fall. Starting from the point in that the cable is stretched out, the jumper begins to slow down until a certain position, where it stops. Of this moment in before, the cable begins to pull the jumper upward. This position, where the jumper inverts the fall sense, it marks his/her largest vertical displacement D regarding the bridge. Naturally that the height of the bridge should be larger than D. it Considers a jumper’s of mass 80 kg hypothetical situation now using an elastic cable of 20 m of length. The elastic constant of the cable is 160 N/m. Calculate the value of D.
Observation: the mass of the cable can be despised in relation to the jumper’s mass. For acceleration of the gravity, use the value 10 m / s²:
The) 20 m.  B) 25 m.  C) 40 m.  D) 36 m.  And) 10 m.”

Being fallen back upon the search motors with the discriminador “bungee jumping” is had, as return, hundreds (or else, thousands) of places; that you/they say everything on the sport, less like him it works really — and this was the objective of the proposed subject exactly. This article has as purpose to fill out this gap and, as it is Science, every suggestion / critic will be well arrival.

I will always maintain in view the solution of the proposed subject and the possible roads for you solve her. Like this, let us enhance the data of the subject:

the jumper’s mass: m = 80 kg
natural length of the cable: L = 20 m
constant elastic of the cable: k = 160 N/m
local acceleration of the gravity: g = 10 m / s²
(to neglect effects of the air and mass of the cable)

We should determine until that distance D will go down the jumper, to count of the bridge.

First solution
In this first direction I will follow the technique of Newton’s laws, verifying the active forces in the system. In a second solution we will use of the conservation of the energy.

Referencial and phases of the process
Let us adopt as reference axis y, in the vertical that contains the point of the jump and, in the bridge we adopt y = 0; the positive sense is ‘down.’ The “jump” presents two different phases.
In the first a free fall is verified (grandma = 0) because the cable still is not being requested; so that, for certain interval of time, in other words, while y < L, the only force agent in the man (therefore, to resultant) is his/her own weight; his/her acceleration is g = constant and his/her speed is that of an object in free fall.

Equacionamento of the first phase

Y < L……. F = P = m.g…… the = g…… v² = 2.g.y…….. (1)

In this phase (1) ….. the = g > 0; v > 0….. as the and v have same sign (the vectors g and v are both vertical ones down, same sense of y), we have a movement evenly accelerated.

When the man’s distance to the bridge, reaches y = L, passed for the second phase: the elastic cable begins being deformed (to stretch out) and raisin to apply a restoring force of the elastic (law of Hooke, f = -k.s) type in the man (f been opposed F). Like this, for y > L the cable will present deformation s = y – L, so that:

Y > L…… f = – k.s = – k. (y – L)…… (2)

The man is represented by the “material point”, (he/she plans black) the gravitational (weight) force for the blue vectors and the elastic (f) force owed to the cable, for the red vectors. For ‘to help’ the presentation, the diagrams are ‘sliding’ for the right, for not happening overlap of vectors. Do notice that, until then, don’t we know where it will happen the maximum deformation (D?).

Equacionamento of the second phase
While y > L, the new resulting force F’ that acts in the man will be:

Y > L………. F’ = P – f = m.g – k. (y – L)…….. (3)

This is a combination of forces that you/they act in opposed senses: a descending force of constant (mg) intensity and an ascending force continually growing, k. (y-L).
Starting from y = L, the force mg continues acting and it stays of constant value, but the contrary elastic force is going increasing of intensity, so that to resultant F’ it is going decreasing of intensity, staying positive until a point B of coordinate yB, where, then, the resulting force is annulled (point of balance of the system; F’ = 0; in the illustration above, blue vector = red vector, / /).
Formally:

y = yB……… 0 = m.g – k. (yB – L)…… yB = L + mg / k….. (4)

For the data of this matter subject it is had:

mg / k = 80.10/160 = 5 m;    yB = 20 + 5 = 25 m.

Note: If the man went going down prisoner slowly to the cable, but being held in a rope, he would be in balance in this point B, distant 25 m of the bridge. It could release the rope, because the cable applies him/her the force equilibrante f = – P.

Once the man goes by the position B (y > yB), his/her descent continues (once he/she still has vertical speed down), but, starting from y = yB, the elastic force becomes every time larger than the weight, so that to resultant he/she starts to have sense appearing upward.

Like this, being applied the Fundamental Beginning of the Dynamics (second law of Newton), it is had:

y > yB….. F’ = mg – k (y-L) = m.a… the = g – (k/m) (y – L)…… (5) (law of acceleration of the movement for y > yB)

With y < L have the = g, the acceleration of the gravity; starting from y = L the acceleration decreases lineally with y because of the action of the cable (it forces restoring of the elastic type that follows the law of Hooke).
When L < y < yB (passage between L and B) the acceleration is positive (to resultant he/she has same sense that the axis; down); when y > yB (passage after B) is negative (resultant has sense contrary to the axis; upward).

Obviously the point B doesn’t characterize the lowest point reached by the man. Observe that while y < yB, the acceleration has the same sign of the speed; like this the man is accelerating. When passing for B the acceleration it changes of sign, but the speed continues positive; this characterizes a retarded movement; the frenamento of the movement begins. In the point B the man has maximum speed!

We know that the acceleration is her derived her of the speed in relation to the time and, as we already learned, a flowed null corresponds to the maximum of the function. Like this, to obtain the maximum value of y we have two roads: (the) to integrate the function acceleration with regard to y to obtain the function of the speed in relation to y — and soon afterwards to annul v (y) to obtain the yD; (b) to work with the definition of acceleration in function of the time and to try to obtain v (y).

Obtaining of the speed
As the answer, I think, to have urgency, I will just present the result of the integration and, to proceed, I will make the complementation, with integral calculation and without using integral calculation; just flowed and consequences.

result of the integration of the function (5):  v² = – (k/m) (y – L) ² + 2.g.y (it repairs well… does one of the portions of that result know?)

Equaling to zero, for y = yD and solving:

- (k/m) (yD – L) ² + 2gy = 0
yD = L + (mg / k) [1 + (1 + 2kL/mg) ½]….. reminding the (4) … yB = L + mg / k….. be:
yD = yB + (yB2 – L2) ½.

For the subject:

yD = 25 + (25² + 20²) ½ = 25 + 225½ = 25 + 15 = 40 m

Complementations
(1) obtaining of the speed quadratic function of y, for integration:

The expression of the acceleration the = g – (k/m) (y – L) it is of the type: THE = THE – B².y, or be,

dv / dt = THE – B².y or, being derived once in relation to the time,

d²v / dt² = – B².v (he/she remembers that dy / dt = v)

This equation differential (typical of MHS), very known, has as solution, the function:

v = grandma.sen (B.t – ß)… (eq.01) or

sen² (B.t – ß) = (v / grandma) ²… (eq.02)

The (eq.01) it can be written: dy / dt = grandma.sen (B.t – ß) that, integrated supplies:

y = (- grandma / B).waistband (B.t – ß) + C or (y – C) ² = (- grandma / B) ².cos² (B.t – ß) or

(y – C) ² = (grandma / B) ².[1 - sen² (B.t - ß)]… (eq.03)

Being taken her/it (eq02) in the (eq.03), it is had:

(y – C) ² = (grandma / B) ².[1 - (v / grandma) ²] or

(y – C) ² / (grandma / B) ² = 1 – (v / grandma) ² or

(v / grandma) ² = 1 – (B / grandma) ².(Y – C) ²

Finally:

v² = vo² – B².(y – C) ² or, with our notations v² = 2.g.y – (k/m) (y – L) ²

To confirm, we will derive that function in relation to the time:2.v.dv / dt = 2.B².(C – Y).dy / dt = 2.B².(C – Y).v or
THE = B².C – B².y, that is the original form of the acceleration, with THE = B².C.

(2) obtaining of the speed quadratic function of y, for derivations and differential:

Of Newton’s second law it resulted:  the = g – (k/m) (y – L)

the = dv / dt… (introducing a change of variables, it comes:)

the = (dv / dy).(dy / dt)… (reminding that: v = dy / dt, is had:)

the = v dv / dy = ½.D (v²) / dy… (then:)

dv² / dy = 2.a = 2g – 2 (k/m) (y – L) or

Dv2/dy = 2g – 2 (k/m) (y – L) = d [2gy - (k/m) (y - L) 2] / dy… (and, finally:)

v2 = 2gy – (k/m) (y – L) 2

Solution of the subject for the method of the energies

Let us indicate for d the experienced deformation for the cable from the position L to the position it exalts where it happens the inversion of the movement. The jumper’s maximum removal, in relation to the bridge, will be: D = L + D.

The jumper’s gravitational potential energy set out from the bridge to this extreme position, he/she turns into elastic potential energy of the cable; we wrote:

m.g. (L+d) = (1/2).k.d²2.m.g.L + 2.m.g.d – k.d² = 0…. dividing m.the.m. for k, and making 2mg/k = u is,

u.L + u.d – d² = 0 (quadratic equation)

d’, d” = [- u ± square (u² +4uL)] / (-2) … formula of Baskara; square = square root.

With the data of the subject, it is had: u = 2mg/k = 2.80.10/160 = 10 and L = 20.

The numeric roots, of the equation, are: d’ = 20 and d” = – 10

Reinforcing: d is the maximum deformation of the cable; increasing L (length of the cable) the jumper’s maximum distance is had to the bridge: D = L+d.

With the data of the subject, a solution is D’ = 20+20 = 40 m and the other is D” = -10+20 = 10 m.

The second solution can be spared because the cable doesn’t apply force in the jumper for y < 20 m.

Bungee jumping is what is considered an extreme sport. It is basically jumping off a platform with an elastic cord tied to the jumper. As the cord is stretched resistance slows the person before they reach the ground. Energy stored in the cord is reduced incrementally as the jumper is oscillated by the rebounding properties of the cord until they come to a state of equilibrium.

Hooke’s Law of Elasticity

One of the most useful physics laws that can be used to explain bungee jumping is Hooke’s Law of Elasticity. Robert Hooke was a British physicist from Great Britain. He lived during the 17th century and created a law that explained the restoring force of a spring.

Hooke’s Law of Elasticity can be expressed as F = -kx. In this formula F represents the amount of force required to restore elastic material to its position of initial equilibrium, k represents the spring constant, which is a constant force and x represents the distance between the fully stretched spring to the initial position of equilibrium.

Potential Energy

The principles of the bungee jumping sport rests in the potential energy that is stored in the spring or the elastic cord used in the sport. The potential energy of the cord can be expressed as U = .5kx^2. This formula will always produce a positive result, as opposed to the Hooke’s Law of Elasticity which has the potential to have oscillating results on both positive and negative sides of a graph.

Oscillation

Oscillation is another physical characteristic of the bungee jumping experience. Oscillation of the jumper can be expressed with the frequency formula: v = 1/(2 X pie) X the square root of (k/m). This formula can be graphed to demonstrate the position of the bungee jumper over time.

Developing a Bungee Jumping Science Fair Project

Students who are interested in creating a science fair project around the extreme sport of bungee jumping have several options. Their first option is to look at how the manipulation of various elements of this sport can increase the intensity of the sport or that can increase the safety of this sport.

Another option that students have is to examine how the forces produced by this sport impact the human body. They can see if the force is harmful or if leads to pleasurable brain chemistry reactions. Students can also examine how the body’s vital statistics change during different stages of the spring’s oscillation frequency.

In order to create an interesting project students will need to be creative. They will also need to push the wow factors with their project. There are many ways to do this including producing simulations of bungee jumping, utilizing video technology to collect data and creating a series of graphics that illustrate the targeted factors are impacted by the experience of bungee jumping.

Conclusion

Bungee jumping can be both terrifying and exciting at the same time. The thrill that it produces is created by the death defying acts that take place while participating in this sport. Physics can be used to explain how death is defied and how forces impact the person’s mind and body.

The first question that comes to mind for this particular extreme sport is, “Why.” Why would you jump off a perfectly good bridge? Or crane? Or why would you jump off a platform? Or hot air balloon? The question that follows closely behind in the observer’s mind goes something like this – “Is that a rubber band tied to their feet?” The answer to the first is simple: To fly, bounce and fly again. To we land based humans, the desire to soar through the air has been with us throughout history. Bungee jumping offers the sensation of flying from the initial free-fall to the repeated rebounds. And, the answer to the second question is, well, yes. It’s a rubber band!

Bungee jumping, or some non-elasticized form of it, has been documented for centuries. As far back as the Aztecs people have been plunging headlong into space with some sort of lifeline tied to their bodies. Back then it was vines – not much give I imagine. Today, the “rubber band” is actually much more that. It is thick pre-stressed braids of latex shock cord. Most jump companies have added a body harness to the attachment fittings for added security. There have been injuries and fatalities, but they are very few considering the several million jumpers since its modern beginnings in 1979. All equipment is provided at the sites whether on a bridge or at a commercial jump site. Just bring your confidence!

There are a couple of variations of bungee jumping around today. One starts you in the reverse position. That is, you are on the ground with one end of the bungee attached to your harness and the other to a crane above. The cord is stretched and stretched and suddenly you are released from the ground to go flying straight up into the air. There are similar rebounds until your momentum wanes. Very thrilling reverse gravity experience! Another lighter than air simulation is the trampoline bungee. You jump normally on a trampoline while attached to a bungee from above. This gives you extra jumping power as the cords are tightened during your acrobatics.

There are many structures worldwide that are used for bungee jumping. These structures include bridges, dams, suspension bridges and towers and are destination sights in and of themselves. The world record for the highest bungee jump occurred at Macau Tower in Macau SAR China at the height of 760 feet. This is a tourist structure and the jump was off the observation deck. The official record keepers only consider jumps from fixed structures to insure accurate measurement. That being said, a jump of 3,157 feet at full cord extension took place from a helicopter in Cancun.

The particular extreme sport is open to most people of reasonably good health. It does not require any special skills. However, you will find that the “skill” of releasing your hands before the jump will suddenly give your trouble. No practice or preparation is required so stay off the roof! Pack up your nerve and head off to the nearest bungee jumping location to experience the thrill of flying. The free-fall is exhilarating as the wind whistles by and ground rushes up. Then you rebound again and again. Like most thrilling adventures, you will want to get back in line for that second jump!